How many grams are there in 1.0 x 10²⁴ molecules of BCl₃?

Answer 1

To determine the number of grams in 1.0 x 10²⁴ molecules of BCl₃, you need to use the molar mass of BCl₃.

The molar mass of BCl₃ is calculated as follows:
B = 10.81 g/mol
Cl = 35.45 g/mol x 3 = 106.35 g/mol
Total molar mass = 10.81 g/mol + 106.35 g/mol = 117.16 g/mol

Next, we will calculate the number of moles in 1.0 x 10²⁴ molecules of BCl₃:
1.0 x 10²⁴ molecules / Avogadro's number = x moles
1.0 x 10²⁴ molecules / 6.022 x 10²³ molecules/mol = 16.6 moles

Finally, we will calculate the number of grams in 16.6 moles of BCl₃:
16.6 moles x 117.16 g/mol = 1946.9 grams

Therefore, there are 1946.9 grams in 1.0 x 10²⁴ molecules of BCl₃.