how many g of Fe2O3 are produced if 3.00 g of Fe reacts?

Answer 1

Fe = 56 g/mol
3 O = 3*16 = 48 g/mol

so a mol of Fe2O3 is 160 grams
and a mol of Fe is 56 grams

3 g Fe = 3/56 mol Fe

that will give me half as many mols of
Fe2O3
so
3/112 mols Fe2O3

(3/112) * 160 = 4.29 grams of Fe2O3
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