How many g of C2H5NH3Cl will be needed to combine with 4.7 g of C2H5NH2 to produce 0.250 L of buffer solution at a pH of 10.00?

I can do this problem with mL and M but not w/out

2 answers

convert the 4.7 g to moles by dividing by the molar mass

you have the L (convert to mL if needed)

then go for it
26.3g?