How many g NO gas can be produced from 120 mL of 2.80 M HNO3 and excess Cu?

3Cu(s) + 8HNO3(aq) ---> 3Cu (NO3)2(aq) + 4H2O(l) + 2NO(g)

1 answer

change 120 ml to l
.120 L
then divide M by L to get moles
2.80 M/.120 L
then take this and multiply it by the atomic weight or mass of NO
Similar Questions
  1. I have a few question for my review.1) How would you prepare 30.0 ml of 0.600M HNO3 From a stock solution of 4.00M HNO3? What
    1. answers icon 4 answers
    1. answers icon 1 answer
    1. answers icon 2 answers
    1. answers icon 1 answer
more similar questions