how many drops of 0.5M NaOH are needed to neutralize 10 drops of 1.0M HCl? What would be the pH of the neutral solution?

Answer 1

drops x M = drops x M
HCl + NaOH ==> NaCl + H2O

The pH of the solution is determined by the salt; in this case, neither the Na^+ nor the Cl^- are hydrolyzed; therefore, the pH will be the pH of pure water.

H2O ==> H^+ + OH^-
(H^+)(OH^-) = Kw = 1 x 10^-14
Solve for (H^+)

Answer 2

1 drop