Asked by Eli
How many digits are in the smallest positive number divisible by th first ten numbers in the Fibonacci sequence?
Answers
Answered by
Reiny
first 10 Fibo numbers:
1 1 2 3 5 8 13 21 34 55
55 = 5x11
34 = 2x17
21 = 3x7
13 = 13
8 = 2x2x2
5 = 5
LCM = 17x11x13x7x5x3x2x2x2 = 2042040 , 7 digits
1 1 2 3 5 8 13 21 34 55
55 = 5x11
34 = 2x17
21 = 3x7
13 = 13
8 = 2x2x2
5 = 5
LCM = 17x11x13x7x5x3x2x2x2 = 2042040 , 7 digits
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