How many digits are in the repeating cycle of 1727?(1 point)

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1 answer

To find the repeating cycle of a decimal representation, we can divide the number by a power of $10$. We have $1727 \div 10000 = 0.1727$. This means that the repeating cycle of $1727$ is the same as the repeating cycle of $0.1727$.

To find the repeating cycle of $0.1727$, we can set up a long division:

$$\begin{array}{c|cc} & 1727 & \\ \cline{2-3} 10000 & 0.1727 & \\ & -10000 & \\ \cline{2-2} & 727 & \\ & \vdots & \\ \end{array}$$

In the long division, we see that the remainder after dividing $727$ by $10000$ is $727$. This means that the repeating cycle of $0.1727$ (and therefore, the repeating cycle of $1727$) is $727$.

So, there is $\boxed{3}$ digits in the repeating cycle of $1727$.