Assuming the 10 boxes are distinguishable or ordered.
There are 10 ways to put the first item, 10 for the second, and 10 for the third. So by the multiplication rule, there are 10^3 ways to place the three objects.
How many different ways can you put 3 distinguishable things in 10 boxes?
3 answers
Okay, but what if the maximum that each box can hold is 2?
What do you do when you have the third object to be placed and supposed to place in a box already filled with two object?
You would skip that case.
How many of these cases do we have?
You would skip that case.
How many of these cases do we have?