The correct answer is D. 2,260.
This is a combination problem since we are choosing a group of toppings from a larger set without regard to order. The formula for combinations is:
nCr = n! / (r! * (n-r)!)
where n is the total number of items, and r is the number of items being chosen.
Plugging in our numbers, we get:
20C3 = 20! / (3! * (20-3)!)
= 20! / (3! * 17!)
= (20 * 19 * 18) / (3 * 2 * 1)
= 1,140
Therefore, the answer is option D. 2,260 is not the correct answer.
How many different ways can you choose 3 frozen yogurt toppings from 20?
A. 6,840
B. 1,140
C. 60
D. 2,260
2 answers
Confusing answer and conclusion by the bot.
Assuming that the order in which the toppings are put in the yogurt
does not matter, the number of ways is
C(20,3) which is 1140
Assuming that the order in which the toppings are put in the yogurt
does not matter, the number of ways is
C(20,3) which is 1140