6P4 = 6! / (6-4)! = 360
There are 6C2 = 15 ways to choose the 4 people, if you don't care where they sit. But there are 4! ways to rearrange the 4 people once they have been chosen. 15*24 = 360
how many different seating arrangements are possible for 6 people in 4 chairs?
I think 15 correct me pls or help me
3 answers
But these 6 people not 4
And there’s 4 chairs
And there’s 4 chairs
there are 6 people
you need to choose 4 of them to be seated (in chairs)
There are 6 choices for the 1st chair
for the 2nd chair, there are now 5 people left to choose from
so, there are 6*5 ways to put people in the 1st 2 chairs.
Then, there are 4 ways to pick the 3rd person
and only 3 ways to pick the 4th person
6*5*4*3 = 360
you need to choose 4 of them to be seated (in chairs)
There are 6 choices for the 1st chair
for the 2nd chair, there are now 5 people left to choose from
so, there are 6*5 ways to put people in the 1st 2 chairs.
Then, there are 4 ways to pick the 3rd person
and only 3 ways to pick the 4th person
6*5*4*3 = 360
2 answers