Asked by Alison
How many different numbers can be made using 4 numbers a b c and d and only + and - ?
Answers
Answered by
Reiny
Your question appears a bit too vague.
Are you allowing only 4 digit numbers, or can you have single, two-digit and three-digit numbers as well?
Can your variables a,b,c, or d take on the value of zero? That would drastically affect our solution.
Are you restricted to integers?? the form a/b is a number.
Please be more specific
Are you allowing only 4 digit numbers, or can you have single, two-digit and three-digit numbers as well?
Can your variables a,b,c, or d take on the value of zero? That would drastically affect our solution.
Are you restricted to integers?? the form a/b is a number.
Please be more specific
Answered by
tchrwill
How many different numbers can be made using 4 numbers a b c and d and only + and - ?
The number of arrangements of 4 different digits is 4! = 4x3x2x1 = 24.
The number of arrangements of the 4 colors is also 24.
Therefore, the number of arrangements of the 4 digits combined with the 4 colors is 24x24 = 576.
The number of arrangements of 4 different digits is 4! = 4x3x2x1 = 24.
The number of arrangements of the 4 colors is also 24.
Therefore, the number of arrangements of the 4 digits combined with the 4 colors is 24x24 = 576.
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