How many different committees can be formed from 9 teachers and 39 students if the committee consists of 2 teachers and 3 students? In how many ways can the committee of 5 members be selected?

Answer 1

number of ways = C(9,2) x C(39,3)
= 36(9139)
= ....

number of committees without restrictions
= C(48,5) = 1712304