HOw many cubic meter of water will an air tight rectangle box with a mass of 8000 kg and dimensions of 10m long 5m wide 3m tall displace when dropped in water? will it float?

Answer 1

V = L*W*h = 10 * 5 8 3 ,
= 150 m^3 = 1.50*10^8 cm^3 = Vol. of box.

Db = 8*10^6g * (1/1.5*10^8cm^3) = 0.0533 g/cm^3 . = Density ofbox.

Dw = 1g/cm^3 = Density of water.

Vb = (Db/Dw)*V,
Vb = (0.0533 / 1)*150 = 8 m^3 = Vol.
below water = Vol. of water displaced.

The box will float, because its' density is less than density of water.

Answer 2

Correction: V = 10 * 5 * 3 = 150 m^3.