mols FeCl3 = 1.00g/molar mass.
mols Cl atoms = 3 times that.
Then mol Cl x 6.02E23 = ?
How many chlorine atoms are contained in a 1.00 g sample of iron(III) chloride, FeCl3? Use the masses to two decimal places from the chart in the front of your text. Use the format 6.02E23 for 6.02 x 1023, or 6.02E-23 for 6.02 x 10-23,use two decimal places in your answer.
4 answers
So I need to multiply 6.02E23 by 3?
No. That's the third step. (Read my answer again. It isn't that garbled.)
Step 1. mol FeCl3 = grams/molar mass
Step 2. mols Cl = 3 x step 1
Step 3. Step 2 x 6.02E23.
Step 1. mol FeCl3 = grams/molar mass
Step 2. mols Cl = 3 x step 1
Step 3. Step 2 x 6.02E23.
3.95*10^23