CuSO4.5H20 count atoms per molecule, I get 21. check that.
Now how many moles of CuSO4.5H2O are in five grams? moles=mass/formulamass
now multiply moles*avagnumber*21
How many atoms of oxygen are there in 5.00g of copper(II) sulfate pentahydrate?
2 answers
CuSO4*5H2O
molar mass= 63.55+32.065+4*16+10*1.01+5*16=250 g/mol
number of moles=mass/molar mass= 5.00 g/ 250 g/mol= 0.02mol
0.02mol* 6,02*10 atoms/mol at power 23 (avogadro's number)= 1.2*10 at power 22 atoms
1.2*10 at power 22 atoms *9= 1.08*10 at power 23 atoms of oxygen.
molar mass= 63.55+32.065+4*16+10*1.01+5*16=250 g/mol
number of moles=mass/molar mass= 5.00 g/ 250 g/mol= 0.02mol
0.02mol* 6,02*10 atoms/mol at power 23 (avogadro's number)= 1.2*10 at power 22 atoms
1.2*10 at power 22 atoms *9= 1.08*10 at power 23 atoms of oxygen.
2 answers