How many atoms of MgO are present in 13.0 moles?

Question

Responses

7.8 x 1024 atoms
7.8 x 10 24 atoms

78 atoms
78 atoms

4.6 x 1022 atoms
4.6 x 10 22 atoms

0.46 atoms

Answer 1

To determine the number of atoms of MgO present in 13.0 moles, we need to use Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 particles (atoms or molecules).

MgO has a 1:1 ratio of Mg to O atoms, so for every one mole of MgO, there is an equal number of moles of Mg and O atoms.

Therefore, the number of atoms of MgO in 13.0 moles is calculated as follows:

Number of moles of MgO = 13.0 moles
Number of atoms of MgO = 13.0 moles x (6.022 x 10^23 atoms/mole) = 7.8 x 10^24 atoms.

So the correct answer is:
7.8 x 10^24 atoms