3,49E23 x 2 = H atom in H2O.
mols CH3OH = 78.1 g/molar mass = ?
mols H atoms = 4 x that number.
Then multiply by 6.02E23. Add H from CH3OH and H2O for total.
How many atoms of hydrogen are in a mixture of 3.49x10^23 molecules of H2O and 78.1g of CH3OH?
2 answers
i dont understand your solution pls can you clarify it