How many atoms of H are in a mixture of 3.49 x 10^23 molecules of H2O and 78.1g of CH3OH?

Answer 1

There will be 3.49 x 10^23 molecules H2O x (2 H atoms/1 molecule H2O) = ?? atoms H.

For CH3OH, mols CH3OH = 71.0/molar mass CH3OH.
1 mol contains 6.02 x 10^23 molecules.
There are 4 H atoms per molecule.

Then add the two together.

Answer 2

Could you explain the steps you did for the first part? Do I multiply 3.49 x 10^23 by the mass of H2O?

Answer 3

You have 3.49 x 10^23 molecules of water. There are 2 H atoms per molcule; therefore, 3.49 x 10^23 x 2 = # atoms of H.

Answer 4

Got it! Thanks