how many atoms of chlorine are ther in 87.56 milligrams of barium chlorite?

Answer 1

Barium chlorite is Ba(ClO2)2.
moles Ba(ClO2)2 in 87.56 mg (0.08756 grams) = grams/molar mass.
There will be 6.022 x 10^23 atoms Ba(ClO2) in 1 mole Ba(ClO2)2.
There are two atoms Cl per mole Ba(ClO2)2. Post your work if you get stuck.

Answer 2

ok. so i have:
Ba 137.33
2Cl 70.9
2O 32
= 240.23

2Cl 70.9/240.23 Xs 100= 29.51%

i need mg not g so i convert it 29.51 in mg =0.02951 correct?
if so i have 0.02951mgCl X 1mol/35.45 X 6.022 X 10 to the 23= 0.00083244 X 6.022= 0.005 X 10 to the 23 power. am i on the correct path?

Answer 3

disregard the last post i meade. i submitted it and i realized i forget to add the87.56 into the work!
Ba 137.33
2Cl 70.9
2O 32
= 240.23

2Cl 70.9/240.23 Xs 100= 29.51%

0.2951 X 87.56mg= 25.84mgCl
25.84 Xs 1mol/35.45= 0.729 X 6.022= 4.39 X 10 to the 23 power. is that correct?

Answer 4

Megan
I'm in Mr. Hartzell's class are you?

Answer 5

yes paul i am. im having a blast trying to do this extra credit. how its it going for you?

Answer 6

I have the molar mass of Ba(ClO2)2 = 272.23
mols Ba(ClO2)2 = 0.08756/272.23 = 3.216 x 10^-4 moles.
6.022 x 10^23 molecules/mole x (3.216 x 10^-4 moles) = 1.937 x 10^20 molecules Ba(ClO2)2. There are 2 atoms Cl for each molecule of Ba(ClO2)2 so the number of Cl atoms will be just twice the amount of molecules Ba(ClO2)2.