How many atom of oxygen are present in 8.8g of carbon(iv)oxide

Answer 1

0.04

Answer 2

Moles CO2 = 8.8-g CO2/44g/mole CO2 = 0.20 mole CO2 x 6.02E23 molecules CO2/mole = 1.204E23 molecules CO2 in the 8.8-gram sample.

#atoms Oxy per CO2 molecule = 2
Therefore, #oxy atoms in 8.8-g CO2 = 1.204E23 molecules CO2 x 2 oxy molecules/CO2 molecule = 2.408E23 oxy atoms in the 8.8-g sample of CO2.

Answer 3

ion