how many 7 digit phone numbers are possible if the first digit cannot be 0 and the other digits can each be any number from 0 through 9

1 answer

A 7-digit phone number can be represented as \( d_1 d_2 d_3 d_4 d_5 d_6 d_7 \), where \( d_1 \) is the first digit and the remaining digits \( d_2, d_3, d_4, d_5, d_6, d_7 \) are the subsequent digits.

  1. For the first digit \( d_1 \):

    • It cannot be 0 and can be any digit from 1 to 9.
    • Therefore, there are 9 possible choices for \( d_1 \) (1 through 9).
  2. For each of the remaining digits \( d_2, d_3, d_4, d_5, d_6, d_7 \):

    • Each can be any digit from 0 to 9.
    • Hence, each of these digits has 10 possible choices.

Now, we can calculate the total number of 7-digit phone numbers by multiplying the number of choices for each digit:

\[ \text{Total numbers} = (\text{choices for } d_1) \times (\text{choices for } d_2) \times (\text{choices for } d_3) \times (\text{choices for } d_4) \times (\text{choices for } d_5) \times (\text{choices for } d_6) \times (\text{choices for } d_7 \]

Substituting in the values:

\[ \text{Total numbers} = 9 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10 \]

This simplifies to:

\[ \text{Total numbers} = 9 \times 10^6 \]

Calculating this gives:

\[ \text{Total numbers} = 9,000,000 \]

Therefore, the total number of 7-digit phone numbers possible, under the given restrictions, is \( \boxed{9000000} \).