how many 0.25-pF capacitors must be connected in parallel in order to store 1.2uC of charge when connected to a battery providing a potential difference of 10v?

Answer 1

C = q/V
so
q = C V
so each stores 2.5 * 10^-12 C
so we need 1.2*10^-6/2.5*10^-12 = .48*10^6
=480,000

Answer 2

1.2x10^-6 / 0.25x10^-12 = 4.8x10^6

Answer 3

but C times ten volts = q per capacitor