How long would it take in minutes to plate 1.00 gram of silver to a watch when 9.2 amps are passed through a silver (I) chloride solution? (atomic mass of silver is 107.8682 g/mol).

Answer 1

I don't know why anyone would use AgCl instead of AgNO3 but that's not here nor there.
Coulombs = amperes x seconds
C = 9.2 A x seconds. So we need to fill in C and seconds.
We know that 96,485 C wil deposit 107.8682 grams of Ag. We want 1 g to be deposited; that will take how many C? That's
96,485 C x (1.0000 g/107.8682) = ? C
Substitute that value for C in
C = 9.2 x seconds and solve for seconds, then convert to min.
One note: the value of 9.2 give you two significant figures so all of those digits for the atomic mass of Ag aren't necessary. Post your work if you get stuck.

Answer 2

Okay, so I did that and I got 97.225 secs or 1.62 minutes