How long would it take a 1.00 x 10^3 W heating element to melt 2.00kg of ice at -20 deg C, assuming all energy is absorbed by the ice?

Answer 1

10^3 * time in seconds t = Joules in
so
10^3 t = 2 kg*2000 J/(kg deg)*(20 deg) + 2 kg (334*10^3 J/kg)

10^3 t = 80* 10^3 J + 668 *10^3 J

t = 748 s or about 12.5 minutes