How long will it take a shell fired from a cliff at an initial velocity of 800m/s at an angle 30 degrees below the horizontal to reach the ground 150m below?

Answer 1

Vo = 800m/s[-30o].
Xo = 800*Cos330 = 693 m/s.
Yo = 800*sin(-30) = -400 m/s.

Y^2 = Yo^2 + 2g*h.
Y^2 = (-400)^2 + 19.6*150 = 162,940
Y = 404 m/s. = Final velocity of ver. component.

Y = Yo + g*Tf.
404 = -400 + 9.8Tf
Tf(Fall time) = ?

Answer 2

30

Answer 3

Excellent calculation

Answer 4

How long will it take a shell fired from a cliff at an initial velocity of 800m/s at an angle of 30degree below the horizontal to reach the ground 1500m below