heat = 0.9 kg * (100ºC - 20ºC) * 4.186 J/g⋅ºC
calculate the heat needed (in Joules)
a Watt is a Joule per second ... 1.2 kW is 1.2 kJ per second
divide the Joules needed by the Watts available to get the seconds (time)
how long will a1.2kw electric kettle take to heat 0.9kg of water from 20 degree celisus to 100 degree celisus
1 answer