How long does it take for the ball to hit the ground 7 meters below if it's thrown straight up wit intial velocity of 2 m/s squared?

Answer 1

Solve this equation for time t:

Vo*t -(g/2)*t^2 = 2t - 4.9 t^2 = -7

Answer 2

can you show me a little more work please I am understanding where you are headed?

Answer 3

I wrote down the equation for height (above the release point) vs. time. It ends up 7 meters below the release point.

Solve the quadratic equation that I set up for you. It will lead to the answer.

You will have to a bit of algebra.

Answer 4

got it thanks.