The density of an object is determined by dividing the mass of an object by its volume.
How is the density of an object determined?(1 point)
Responses
by subtracting the mass of an object from its volume
by subtracting the mass of an object from its volume
by adding the volume of an object to its mass
by adding the volume of an object to its mass
by multiplying the volume of an object by its mass
by multiplying the volume of an object by its mass
by dividing the mass of an object by its volume
9 answers
Responses
32 kg/m
32 kg/m
120 kg/m2
120 kg/m2
60 kgm
60 kgm
5 kg/m3
To calculate the density, you can use the formula:
\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]
First, determine the volume of the cube. The volume \(V\) of a cube with side length \(s\) is given by:
\[ V = s^3 \]
For a cube with a side length of 2 meters:
\[ V = 2^3 = 8 , \text{m}^3 \]
Now, plug the mass (40 kg) and the volume (8 m³) into the density formula:
\[ \text{Density} = \frac{40 , \text{kg}}{8 , \text{m}^3} = 5 , \text{kg/m}^3 \]
So, the density of the cube is 5 kg/m³.
Responses
9 square centimeters
9 square centimeters
3 cubic centimeters
3 cubic centimeters
6 square centimeters
6 square centimeters
27 cubic centimeters
The volume \(V\) of a cube can be calculated using the formula:
\[ V = s^3 \]
where \(s\) is the side length of the cube.
For a cube with a side length of 3 centimeters:
\[ V = 3^3 = 27 , \text{cubic centimeters} \]
Thus, the volume of the cube is 27 cubic centimeters.
Responses
what the weight of the object is
what the weight of the object is
what amount of space the object takes up
what amount of space the object takes up
how compact the object is
how compact the object is
how much matter the object has
The density of an object tell you how compact the object is.
Responses
the density of the tree
the density of the tree
the height of the tree
the height of the tree
the volume of the tree
the volume of the tree
the mass of the tree
The term that describes the amount of matter in a tree is the mass of the tree.