How fast must the ball rolled along the surface of a 70cm high table so that when it roll off the edge it will strike the floor at the same distance (70cm) from the point directly below the edge of the table.

Answer 1

h= g•t^2/2 => t =sqrt(2•h/g)= =sqrt(1.4/9,8)=0.38 s.
L =v(x) •t => v(x) = L/t =
=0.7/0.38 =1.85 m/s.

Answer 2

h= g•t^2/2 => t =sqrt(2•h/g)= =sqrt(1.4/9,8)=0.38 s.
L =v(x) •t => v(x) = L/t =
=0.7/0.38 =1.85 m/s.