how far will a stone travel over level ground if it is thrown upward at an angle 30 with the horizontal and with a speed of 12m/s?what maximum range could be achieved with the same initial speed?

Answer 1

horizontal velocity=12cos30
vertical initial velocity:12sin30

time in air:
hf=hi+vi'*t-4.8t^2
hf=0 Hi=? assume zero, as stupid as that is.
0=12sin30*t-4.8t^2
t=sqrt(12sin30/4.8)

the horizontal distance:
horizontal velocity above*timeinair

Max range will occur at theta 45 deg. Figure it as above.

Answer 2

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