How far will a body move in 4seconds if uniformly accelerated from rest at the rate of 2ms-2

Answer 1

To find the distance covered by the body in 4 seconds with a uniformly accelerated motion, we can use the formula:

\[s = ut + \frac{1}{2}at^2\]

where:
s = distance covered
u = initial velocity (0 m/s as it starts from rest)
t = time taken (4 seconds)
a = acceleration (2 m/s²)

Plugging in the values, we have:

\[s = (0)(4) + \frac{1}{2}(2)(4^2)\]
\[s = 0 + \frac{1}{2}(2)(16)\]
\[s = 0 + (1)(16)\]
\[s = 16\text{ m}\]

Therefore, the body will move a distance of 16 meters in 4 seconds.