1/2 k x^2 = 1/2 m v^2 ... x = v √(m / k) ... x = 3.8 √(10 / 4777)
significant figures are the only thing that comes to mind
... the mass is one sig fig ... so the result should be also
How far was the spring stretched from its unstreched length?
A mass m = 10 kg rests on a frictionless table and accelerated by a spring with spring constant k = 4777 N/m. The floor is frictionless except for a rough patch. For this rough path, the coefficient of friction is μk = 0.43. The mass leaves the spring at a speed v = 3.8 m/s.
so I got .17... but it's not correct, I used 3.8 sqrt(10/4777)
what am I doing wrng?
1 answer