130 is in Joules
7.20 and 25.0 are in MicroCoulomb and the answer has to be in cm
How far must the point charges = 7.20 and = -25.0 be separated for the electric potential energy of the system to be -130 ?
2 answers
Require that
k Q1*Q2/R = -130 J
k is the Coulomb constant,
8.99*10^9 N/C^2*m^2
Q1 = 7.2*10^-6 C
Q2 = 25.0*10^-6 C
Solve for R, which
R will be in meters.
Convert it to cm
k Q1*Q2/R = -130 J
k is the Coulomb constant,
8.99*10^9 N/C^2*m^2
Q1 = 7.2*10^-6 C
Q2 = 25.0*10^-6 C
Solve for R, which
R will be in meters.
Convert it to cm