To find the coordinate for the center of the four square court, we need to find the average of the x-coordinates and the average of the y-coordinates of the four corners of the court.
The four corners of the court can be represented as (-20, 20), (20, 20), (-20, -20), and (20, -20).
Average of x-coordinates = ( -20 + 20 + -20 + 20 ) / 4 = 0 / 4 = 0
Average of y-coordinates = ( 20 + 20 + -20 + -20 ) / 4 = 0 / 4 = 0
Therefore, the coordinate for the center of the four square court is (0, 0).
How far are you throwing the ball? Show your work to receive credit. Answers should be in simplest radical form. (2 points)
To find the distance between two points (-3,7) and (7,-3) we need to use the distance formula and solve.
Square root ((7- (-3) )^2 + (-3 - 7)^2)
= square root ((10)^2 + (-10)^2)
=square root (100 + 100)
= square root 200
=10 square root 2
So i'm throwing the ball a distance of 10 square root 2
5. What is the coordinate for the center of the four square court? Show your work to receive credit. (2 points)
1 answer