How does the volume of a cone change when the radius is quadrupled and the height is reduced to 2004-06-01-04-00_files/i0300000.jpg of its original size

Answer 1

oldv = 1/3 pi r^2 h

Now replace r with 4r and h with whatever fraction of h, say, 1/n, it has become.

new v = 1/3 pi (4r)^2(1/n * h)
= 1/3 pi * 16r^2 * h/n
= oldv * 16/n

Answer 2

what is the answer