Same charge, not hooked to an outside source?
Energy=1/2 Q^2/Ck where C is the dry air capacitance, and k is the dielectric costant. Hmmm,so energy stored is reduced. That must mean it did work on the person trying to force the dielectric into the gap.
What if it is constant voltage, hooked to a voltage source?
Energy=1/2 CkV^2 now energy is increased, which means the outside circuit must have suppied energy.
how does the total energy stored in a capacitor change, when the medium of air is replaced by a medium of dielectric constaant K? Explain.
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