To determine the concentration of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters). In this case, you are given that you have 10 g of Cu(OH)2 dissolved in 100 mL of solution.
First, convert the mass of Cu(OH)2 into moles. The molar mass of Cu(OH)2 can be calculated by adding the atomic masses of Cu, O, and H:
Cu: 63.55 g/mol
O: 16.00 g/mol (there are two oxygen atoms)
H: 1.01 g/mol (there are two hydrogen atoms)
Molar mass of Cu(OH)2 = (63.55 g/mol) + (2 × 16.00 g/mol) + (2 × 1.01 g/mol) = 97.55 g/mol
Now, calculate the number of moles of Cu(OH)2:
moles of Cu(OH)2 = mass / molar mass = 10 g / 97.55 g/mol ≈ 0.1023 mol
Next, convert the volume of the solution from milliliters to liters:
volume of solution = 100 mL = 100/1000 L = 0.1 L
Finally, calculate the concentration (Molarity) of the solution by dividing the moles of Cu(OH)2 by the volume of the solution in liters:
concentration (Molarity) = moles of solute / volume of solution
= 0.1023 mol / 0.1 L = 1.023 M
Therefore, the concentration of the 100 mL solution of 10 g of Cu(OH)2 is approximately 1.023 M (not 0.02 M).
how does the concentration of a 100 mL solution of 10 g of Cu(OH)2 equals to .02M?
1 answer