How does the Closure Property prove that the sum of a rational and irrational number is irrational?

1.Irrational numbers can be added or subtracted.
2.The sum or difference of a rational and irrational number is a rational number.
3.The sum or difference of two rational numbers is a rational number.
4.The sum of an irrational and rational number can’t be predicted.

1 answer

To understand how the closure property applies to proving that the sum of a rational number and an irrational number is irrational, we first need to clarify what rational and irrational numbers are:

  • A rational number can be expressed as the fraction \(\frac{a}{b}\), where \(a\) and \(b\) are integers and \(b \neq 0\).
  • An irrational number cannot be expressed as a fraction of integers; it has a non-repeating, non-terminating decimal expansion.

Now, let's analyze the provided statements:

  1. Irrational numbers can be added or subtracted.

    • This statement is true, but it doesn't directly prove anything about the sum of a rational and irrational number.
  2. The sum or difference of a rational and an irrational number is a rational number.

    • This statement is actually false. If this were true, it would contradict the definition of irrational numbers. Therefore, it cannot be used in the proof.
  3. The sum or difference of two rational numbers is a rational number.

    • This statement is true due to the closure property of rational numbers, but it does not pertain directly to the sum of a rational and an irrational number.
  4. The sum of an irrational and rational number can’t be predicted.

    • This statement is vague. While it touches on the uncertainty regarding the outcome of adding a rational and an irrational number, it's not a formal proof.

To prove that the sum of a rational number and an irrational number is irrational, we typically use the following reasoning:

  • Let \( r \) be a rational number and \( x \) be an irrational number.
  • If the sum \( r + x \) were to be rational, we could isolate \( x \) as follows: \( x = (r + x) - r\).
  • Since \( r \) is rational, and if the sum \( r + x \) is also rational, then \((r + x) - r\) would also be rational (as the difference of rational numbers is rational).
  • This would mean that \( x \) would have to be rational, which contradicts our assumption that \( x \) is irrational.

Thus, the conclusion is that the sum \( r + x \) must be irrational.

In summary, the only statements that would logically lead you toward proving the irrationality of the sum would be the properties of rational and irrational numbers, with 2 being crucially important to note as false in proving the original statement.