How does the Closure Property prove that the sum of a rational and irrational number is irrational?(1 point) Responses The sum or difference of two rational numbers is a rational number. The sum or difference of two rational numbers is a rational number. Irrational numbers can be added or subtracted. Irrational numbers can be added or subtracted. The sum of an irrational and rational number can’t be predicted. The sum of an irrational and rational number can’t be predicted. The sum or difference of a rational and irrational number is a rational number.

1 answer

The correct response is: The sum or difference of two rational numbers is a rational number.

To elaborate on the reasoning:

  1. Definition of Rational and Irrational Numbers:

    • A rational number can be expressed as the fraction of two integers, \( \frac{a}{b} \), where \( b \neq 0 \).
    • An irrational number cannot be expressed as a simple fraction, meaning its decimal representation is non-repeating and non-terminating.
  2. Closure Property:

    • The closure property states that when you combine two numbers within a specific set (like rational numbers), the result will also be within that set. For rational numbers, the sum or difference of two rational numbers is a rational number.
  3. Adding Rational and Irrational Numbers:

    • Let \( r \) be a rational number and \( i \) be an irrational number. If the sum \( r + i \) were rational, then it could be expressed in the form \( \frac{a}{b} \) (rational).
    • Rearranging gives us \( i = (r + i) - r \). Since \( (r + i) \) is assumed rational and \( r \) is rational, their difference must also be rational.
    • However, this contradicts the fact that \( i \) is irrational.

Thus, the sum of a rational number and an irrational number must be irrational, confirming that the closure property leads to an understanding that the mix results in an irrational number.