Asked by mary
How does Le Chatelier's principle explain the result you obtained when you added HCL to a suspension of Ca(OH)2 in water? Where the result was, precipiatate dissappeared and an increase in temperature resulted.
Answers
Answered by
bobpursley
Ca(OH)2+ HCl <> CaCl2 + H20 + energy
you add more HCl,
Keq= [CaCl2]/[Ca(OH)2][HCl]
you add more HCl, to reestablish equilibrium, more CaCl2 is made, and less Ca(OH)2 is left.
you add more HCl,
Keq= [CaCl2]/[Ca(OH)2][HCl]
you add more HCl, to reestablish equilibrium, more CaCl2 is made, and less Ca(OH)2 is left.
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