consider a cube.
v = s^3
a = 6s^2
v/a = s/6
That is, the ratio increases as the side length increases. If you check out any other shape, you will see that since the volume grows as the cube and the area grows as the square, the ratio continues to grow at a rate proportional to the size.
How does increasing the size of an object affect it's volume to surface area ratio?
I don't understand please explain it?
2 answers
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on fortnight !!!!!!
on fortnight !!!!!!
2 answers