How does .08/(.08+.92(2/23)^t/4) become 2/(2+23(2/23)^t/4)? I don't understand how .08 becomes 2 and .92 becomes 23.

Answer 1

Divide numerator and denominator by .04

Answer 2

They multiplied top and bottom by 25
.08/(.08+.92(2/23)^t/4)
= .08(25) / [(25) ((.08+.92(2/23)^t/4) ]
= 2 / (2 + 23(2/23)^t/4 )

Answer 3

notice Jerry's answer and mine are the same thing, since

k ÷ .04
= k x 1/.04
= k x 25