x^2+y^2+x+y-1/4=0
x²+y²+x+y=1/4
x²+(1/2)²+x+[y²+(1/2)²+y]=1/4+2(1/2)²
(x+1/2)²+(y+1/2)²=(1/4+1/2)
(x+1/2)²+(y+1/2)²-3/4=0
how do you write the equation: x^2+y^2+x+y-1/4=0 in standard form and factored form?
1 answer