How do you write a redox reaction in an acidic environment for this?

Cu^+2 + I- => CuI + I2

I understand that you get these equations for redox, but how do you put them in an acidic environment when there are no oxygens in the equation?

2I- => I2 + 1 electron
1 electron + Cu^+2 => CuI

Similar Questions
  1. Please write down the redox reactions (using the half-reaction method!)a)Cl2 from OCl- and Cl- in acidic solution b)Br2 from
    1. answers icon 2 answers
  2. Balance the following redox reaction in acidic and basic solutions:Fe(OH)2(s) + O2(g) --> Fe(OH)3(s) These are the steps my
    1. answers icon 0 answers
    1. answers icon 1 answer
  3. In a particular redox reaction, NOis oxidized to NO−3 and Ag+ is reduced to Ag . Complete and balance the equation for this
    1. answers icon 1 answer
more similar questions