Asked by Anonymous
How do you write a balanced equation for the preparation of phenylmagnesium bromide and it's reaction with benzophenone followed by neutralization in acid?
Answers
Answered by
DrBob222
C6H6Br + Mg ==> C6H6MgBr which is the phenylmagnesium bromide.
C6H6MgBr + C10H13O ==> C16H19OMgBr
C16H19OMgBr + H2O(H^+) ==> C16H19OH + MgOHBr.
I can't draw the structures. I think I've counted the C, H, O etc but you should check it out.
The follows this scheme.
BrBenzene + Mg ==> Benzene*MgBr
Benzene*MgBr + BzCOBz ==>
R3COH where R is phenyl group.
C6H6MgBr + C10H13O ==> C16H19OMgBr
C16H19OMgBr + H2O(H^+) ==> C16H19OH + MgOHBr.
I can't draw the structures. I think I've counted the C, H, O etc but you should check it out.
The follows this scheme.
BrBenzene + Mg ==> Benzene*MgBr
Benzene*MgBr + BzCOBz ==>
R3COH where R is phenyl group.
Answered by
Lisa
so what is the exact anwser?
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