How do you write a balanced equation for the preparation of phenylmagnesium bromide and it's reaction with benzophenone followed by neutralization in acid?

Answer 1

C6H6Br + Mg ==> C6H6MgBr which is the phenylmagnesium bromide.

C6H6MgBr + C10H13O ==> C16H19OMgBr

C16H19OMgBr + H2O(H^+) ==> C16H19OH + MgOHBr.
I can't draw the structures. I think I've counted the C, H, O etc but you should check it out.
The follows this scheme.
BrBenzene + Mg ==> Benzene*MgBr
Benzene*MgBr + BzCOBz ==>
R3COH where R is phenyl group.

Answer 2

so what is the exact anwser?