Volume is 4/3 PI r^3, and Surface area of a sphere is 4PI r^2
Lets look at SurfaceArea/Volume
S/V=4PIr^2/(4/3 PI r^3)= 3/r
what happens as r goes to zero?
So it seems that smaller r is more effective is one is looking for surface area.
How do you solve this problem?
In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a shpere) is 10.0cm^3. Calculate the surface area of the catalyst. IF the sphere is broken down into eight spheres, each having a volume of 1.25 cm^3, what is the total surface area of the spheres? Which of the two geometric configurations of the catalyst is more effective? (The surface area of a shpere is 4pir^2). Based on your analysis here, explain why it is sometimes dangerous to work in grain elevators?
1 answer
1 answer