The formula
A
=
1
2
h
(
b
1
+
b
2
)
A=12h(b1+b2) gives the area,
A
A, of a trapezoid with parallel sides of length
b
1
b1 and
b
2
b2 and perpendicular height,
h
h .
How do you solve these types of math problems.
Directions: Solve each literal equation for the indicated variable.
A=1/2h(B+b) (For b) Area of a trapezoid
It is just a matter of algebraic manipulation.
A=(1/2)h(B+b)
Multiply both sides of the equation by 2/h.
B+b = 2A/h
b = (2A/h) - B
2 answers
How do I solve the literal equation for y