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how do you solve the following questions using the substitution method?

-3x-y=3 3x+6y=48
-3x-5y=-21 -5x+6y=32

2x+4y=12
4x+16y=8

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Substitution? I would solve for x in the first equation:

x=6-2y check that. Then put that for x into the second equation...

4(6-2y)+16y=8 and solve for y.

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