How do you solve the following problems? I get confused, can anyone help? Thanks.
(7a^5-a^3)-(a^5-5a^3-1)
(5x-3)(x^3-5x+2)
(4w+5z)^2
3 answers
does it tell you what the variables represent?
for addition and subtraction, just collect terms with the same power
(7a^5-a^3)-(a^5-5a^3-1)
7a^5-a^3-a^5+5a^3+1)
(7-1)a^5 + (-1+5)a^3 + 1
4a^5 + 4a^3 + 1
When multiplying, use the distributive property
(5x-3)(x^3-5x+2)
(5x)(x^3-5x+2) - 3(x^3-5x+2)
5x^4-25x^2+10x-3x^3+15x-6
5x^4-3x^3-25x^2+25x-6
You can do the squared binomial as the one above, or recall that
(a+b)^2 = a^2 + 2ab + b^2
so, you have
(4w+5z)^2
= (4w)^2 + 2(4w)(5z) + (5z)^2
= 16w^2 + 40wx + 25z^2
(7a^5-a^3)-(a^5-5a^3-1)
7a^5-a^3-a^5+5a^3+1)
(7-1)a^5 + (-1+5)a^3 + 1
4a^5 + 4a^3 + 1
When multiplying, use the distributive property
(5x-3)(x^3-5x+2)
(5x)(x^3-5x+2) - 3(x^3-5x+2)
5x^4-25x^2+10x-3x^3+15x-6
5x^4-3x^3-25x^2+25x-6
You can do the squared binomial as the one above, or recall that
(a+b)^2 = a^2 + 2ab + b^2
so, you have
(4w+5z)^2
= (4w)^2 + 2(4w)(5z) + (5z)^2
= 16w^2 + 40wx + 25z^2
No it does not tell you what the variables represent.
I'm still a little confused but thank you Steve for your help. :)
I'm still a little confused but thank you Steve for your help. :)
0 answers