How do you solve second order initial value problems?
I don't understand how would solve these questions..for example
(d^2 y)/(dx^2 )=24x^2-10. When x=1, dy/dx = 3, and y = 5.
Can anyone explain how?
I don't understand how would solve these questions..for example
(d^2 y)/(dx^2 )=24x^2-10. When x=1, dy/dx = 3, and y = 5.
Can anyone explain how?
0 answers
0 answers
1 answer
1 answer